Question

I don’t know how to solve these graphs. Can you please help me?

Answer 1

The equation of the line with slope m and y-intercept b is given by:

`y=mx+b`

In this case the slope is 5 and the y-intercept is -2; then we have that the equation of the line is:

`y=5x-2`

Now that we have the equation of the line we can use it to find points on the line, we do that by given values to x (whichever values we want) and use the equation to determine its corresponding y value.

If x=0, then we have:

`\begin{gathered} y=5(0)-2 \\ y=-2 \end{gathered}`

Hence, the line passes through the point (0,-2).

If x=1, then we have:

`\begin{gathered} y=5(1)-2 \\ y=5-2 \\ y=3 \end{gathered}`

Hence, the line passes through the point (1,3).

Now that we have two points on the line we graph them on the plane:

Finally, we join the points with a straight line. Therefore, the graph of the line is: