Question

Find x
so the distance between
(x,4)
and
(2x-4,-5)
is
15

Answer 1

`(2x-4-x)^2 + (-5-4)^2 = 15^2\\ (x-4)^2 + (-9)^2 = 225\\ x^2 - 8x + 16 + 81 - 225 = 0\\ x^2 - 8x -128 = 0\\ x= (8б √((-8)^2-4*1*(-128)) )/(2)=(8б √(576) )/(2)= (8б 24 )/(2)= (2(4б 12) )/(2)= 4б12 \\ x_1=4-12=-8 \\ x_2=4+12=16`