Question

A horse owner has 50 lbs of hay that is 6% protein by weight. He adds x lbs of oats that is 12% protein by weight.

The function y=.06(50)+.12x/50+x
models the percent of protein, y, in the final mixture of feed. What is the y-intercept of the function that models the percent of protein in the final mixture?
y-intercept=

Answer 1

y-intercept = 0.06 = 6%

Explanation:

As per the statement:

A horse owner has 50 lbs of hay that is 6% protein by weight. He adds x lbs of oats that is 12% protein by weight.

Given the function:

`y = (0.06(50)+0.12x)/(50+x)`

where, y represents the percent of protein in the final mixture of feed.

We have to find y-intercept of the function that models the percent of protein in the final mixture.

Y-intercept:

Substitute x = 0 and solve for y:

then;

`y = (0.06(50)+0.12(0))/(50+0)=(0.60 \cdot 50)/(50)`

⇒
`y = 0.06 =6\%`

Therefore, the y-intercept of the function that models the percent of protein in the final mixture is, 6%