Question

There is a 65% chance that Mom will order Chinese take-out for dinner, 45% chance that she will take you to a movie, and a 70% chance that she will order both Chinese take out and take you to a movie. What is the chance that she will order Chinese take out or take you to a movie ? (Hunt: probability of unions )

Answer 1

P(A)=0.65
P(B)=0.45
P(AnB)=0.70
P(AnB)=0.65+0.45-0.70=0.40
40% chance that mom will order chinese food and take you to a movie

Answer 2

Yeah, thanks:

P(AUB)=P(A)+P(B)-P(A and B) = .65+.45-.7 = .4, 40%