Question

3logbase5(x^2+9)-6=0

Can somebody help me solve this please? If you can, don't just say the answer, I want to understand how to do this so an explanation would come in handy please and thank you. ^^

Answer 1

`3\log_5(x^2+9)-6=0`

`3\log_5(x^2+9)=6`

`\log_5(x^2+9)=2`

`5^(\log_5(x^2+9))=5^2`

`x^2+9=25`

`x^2=16`

`x=\pm√(16)`

`x=\pm4`