Question

An object with a mass of 78 kg is lifted through a height of 6 meters how much work is done

Answer 1

We got the following:
m = 78kg
h = 6m
g = 9.8 m/
`sec^(2)` ≈ 10 m/
`sec^(2)`
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A = ?

As we know A = Ep = mgh -> potential energy
so the answer would be A = 78 * 6 * 10 = 4680 Joule