perimeter = 2L +2W
the problem states the length ( L) is 2 meters longer then width, so L = w+2
so perimeter =2(w+2) +2w
24 = 2(w+2) +2w
24 = 2w+4 +2w
24 = 4w+4
20=4w
w=20/4 = 5
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