Question

If the velocity of an object changes from 65 m/s to 98 m/s during a time interval of 12 s, what is the acceleration of the object?

A. 13.58 m/s
  B. 2.75 m/s
  C. 33 m/s
  D. 5.42 m/s

Answer 1

The answer is 2.75 m/s. you can get it by using a formula (v-u)/t.

Answer 2

`Given:\\v_0=65 (m)/(s) \\v_1=98(m)/(s)\\t=12s\\\\Find:\\a=?\\\\Solution:\\\\a= (\Delta v)/(t) \\\\\Delta v=v_1-v_0\\\\a= (v_1-v_0)/(t) \\\\a= (98(m)/(s)-65(m)/(s))/(12s) =2,75 (m)/(s^2) \\\\Answer\;\;B`