42.2k views
0 votes
Find the x intercepts of the parabola with vertex (5,-12) and y intercept (0,63)

1 Answer

3 votes

The equation for the standard form of parabola is given as:

y = A (x - h)^2 + k

with (h, k) being the (x, y) coordinates of the vertex

For the given problem, we are given that (h, k) = (5, - 12).
We can then use point (0, 63) for x and y to solve for A
63 = A (0 - 5)^2 - 12
75 = A (25)

A = 75 / 25

A = 3

Equation of given parabola:
y = 3 (x - 5)^2 - 12


We can now solve for the x –intercept:
Set y = 0, then solve for x

0 = 3 (x - 5)^2 - 12

3 (x - 5)^2 = 12

(x - 5)^2 = 4

Taking sqrt of both sides
x - 5= ±2

x = -2 - 5 = -7 and x = 2 - 5 = - 3
x = -3, -7


Answer:
x-intercepts of given parabola: -3 and -7

(-3, 0) and (-7, 0)

User Alphazero
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories