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A compound analyzed as 18.0% carbon, 2.26% hydrogen, and 79.7% chlorine. calculate the empirical formula of the compound.

User Shunan
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To answer this item, our basis is 100g. We solve for the masses of the given elements in this item,

carbon: (0.18)(100 g) = 18 g
hydrogen: (0.0226)(100 g) = 2.26 g
chlorine: (0.797)(100 g) = 17.7 g

Then, we calculate for the number of moles by dividing the masses by the molar masses of the given elements.

Number of moles:

carbon = (18 g) x (1 mol / 12 g) = 1.5 moles
hydrogen = (2.26 g) x (1 mol/ 1.01 g) = 2.23 moles
chlorine = (79.7 g) x (1 mol / 35.45 g) = 2.25 moles

We get the ratio of the number of moles by dividing them with the lowest value, 1.5.
Carbon = 1.5 moles / 1.5 = 1
Hydrogen = 2.23 moles / 1.5 = 1.48
Chlorine = 2.25 / 1.5 = 1.5

The empirical formula is,
C1H1.5CL1.5
Simplifying,
C2H3Cl3
User Fatemeh Majd
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