Answer:
f(x)=6 at x=6
Therefore, option 4 is correct.
Explanation:
We have been given a function:
![f(x)= [tex]f(x)=\begin{cases}3x^2+1 & \text{ if } -4<x<6 \\ 6 & \text{ if } 6\leq x<9 \end{cases}](https://img.qammunity.org/2018/formulas/mathematics/high-school/jebovfivt6e57m2uocarw16zvqvnebtob6.png)
We have to find the value of f(x) where x =6
The function is 6 at x= 6 from the definition of the function. Because equal to sign is with 6
Therefore, option 4 is correct.