How many grams of h3po4 are in 521 ml of a 9.30 m solution of h3po4?

asked Jun 22, 2018 197k views

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4 votes

v=521 ml = 0.521 L
c=9.30 mol/L
M(H₃PO₄)=98.00 g/mol

n(H₃PO₄)=cv
m(H₃PO₄)=n(H₃PO₄)M(H₃PO₄)=cvM(H₃PO₄)

m(H₃PO₄)=9.30*0.521*98.00=474.84 g

Dory Zidon answered Jun 29, 2018

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