Question

Solve log_x(1/32)=-5

Answer 1

remember


`log_a(b)=c` translates to
`a^c=b`

so

`log_x((1)/(32))=-5` translates to
`x^(-5)=(1)/(32)`
remember, if a^b=c^b when b=b, then a=c
and x^-m=1/(x^m)

hmm

`x^(-5)=(1)/(32)`

`(1)/(x^5)=(1)/(32)`
32=x⁵
5th root both sides
2=x
x=2