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in triangle ABC, < A is the right angle, and m< B =45. find BC. if your answer is not the whole number, leave it in the simplest radical form

User Ibex
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1 Answer

23 votes
23 votes

\measuredangle B=45,\text{ }\measuredangle A=90,\text{ }\measuredangle C=45
AC=11,\text{ BC=?}
\sin (\measuredangle B)=(AC)/(BC)
\sin (45)=(11)/(BC)
\frac{\sqrt[]{2}}{2}=(11)/(BC)
BC=\frac{11\cdot2}{\sqrt[]{2}}
BC=11\sqrt[]{2}

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