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Find the zeros of the function. f(x) = 9x3 - 72x2 + 135x
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Find the zeros of the function.

f(x) = 9x3 - 72x2 + 135x

User Endophage
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9x3=27; 72x2=144 so the right side condenses to 135x-117
f (x)=135x-117
so this function crosses the y axis at -117 and the x axis at .866666666 repeating.
User Joe Pallas
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9x³-72x²+135x=0
9x(x²-8x+15)=0
9x(x-5)(x-3)=0
x=0 or 5 or 3
☺☺☺☺
User YulkyTulky
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