Question

PLEASE SHOW WORK! WORTH 40 POINTS!!!!!!!

From points A and B, the distance between in which is 1020 mi. Two trains left simultaneously towards each other. The speed of one train was 10 mph greater than the speed of the other. In 5 hours the train had not met yet and were 170 mi apart. Find the speed of both trains.

Answer 1

From points A and B, the distance between which is 1020 mi

The speed of one train was 10 mph greater than the speed of the other one

Let the Speed of first train is x

Speed of second train is x+ 10

Time = 5 hours

Distance = speed * time

Distance traveled by first train = x * 5= 5x

Distance traveled by second train = (x+10) * 5= 5x + 50

the trains had not met yet and were 170 mi apart.

the distance between A and B is 1020 mi, Distance traveled by two trains = 1020 - 170 = 850 miles

Distance traveled by first train + second train = 850

5x + 5x + 50 = 850

10x + 50 = 850

Subtract both sides by 50

10x = 800

x= 80

Speed of first train is 80 miles per hour

Speed of second train is 90 miles per hour

Answer 2

80 and 90 mph

Explanation:

Given that A and B have a distance of 1029 miles between them. Two trains each start from A and B and move towards each other.

Let the speed of I train be s

Then speed of second train = s+10 (since 10 greater than speed of I train)

Relative speed = s+s+10 = 2s+10

In 5 hours they travelled together a distance of 1020-170 =850 miles

Distance travelled = 850 miles

Relative speed = 2s+10

Time taken = 5 hours

Since distance = time x speed

we have

5(2s+10) =850

2s+10 =170

s = 80

Speed of the trains are 80mph and 90 mph