63.2k views
4 votes
When the function f(x) = 3(5)x is changed to f(x) = 3(5)x + 22, what is the effect? There will be no change to the graph because the exponential portion of the function remains the same. The y-intercept is 22 spaces higher. The x-intercept is 22 spaces higher. All input values are moved 22 spaces to the right.

User Wizztjh
by
7.7k points

2 Answers

6 votes
The y-intercept is 22 spaces higher.  Adding a constant to a function shifts the parent function upwards by that number of units.
User Sajad
by
8.4k points
2 votes

Answer: The y-intercept is 22 spaces higher.


Step-by-step explanation: Given function is
f(x) = 3(5)^x.

And transformed function equation
f(x) = 3(5)^x + 22.

We can see 22 is being added to the given function f(x) to get the transformed function.

Note: According to transformation rule, y = f(x) +k shift k units up.

22 is being added to the original function. So,
f(x) = 3(5)^x + 22 function would shift 22 units up that is y-intercept is 22 spaces higher.

Therefore , correct option is : The y-intercept is 22 spaces higher.


User Ben Sidhom
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.