Question

An electric field exerts force of 2.60 N on a 3.40 x 10-8 C charge. What is the magnitude of the electric field?Group of answer choices7.65 x 107 N/C8.43 x 107 N/C9.05 x 107 N/C12.0 x 107 N/C

Answer 1

`7.65\cdot10^7N\/C`

Step-by-step explanation

We want to find the magnitude of the electric field.

To do this, we have to apply the formula for electric field:

`E=(F)/(q)`

where F = force exerted on the charged particle

q = electric charge on the particle

Hence, the magnitude of the electric field is:

`\begin{gathered} E=(2.60)/(3.40\cdot10^(-8)) \\ E=7.65\cdot10^7N\/C \end{gathered}`

The correct answer is the first option.