Question

I need help with this question please. It is non graded.

Answer 1

Given:

The graph of the quadratic equation is given. The intersecting points on the graph are (-6,0) and (0,0).

Required:

To find the equation of the parabola.

Step-by-step explanation:

The intercept points are given on the graph.

when x= -6 , y =0

Put x = -6 in the given option and find the value of y.

`\begin{gathered} y=x^2+6x \\ y=(-6)^2+6(-6) \\ y=36-36 \\ y=0 \end{gathered}`
`\begin{gathered} y=x^2-6x \\ y=(-6)^2-6(-6) \\ y=36+36 \\ y=72 \end{gathered}`
`\begin{gathered} y=x^2+6x-12 \\ y=(-6)^2+6(-6)-12 \\ y=36-36-12 \\ y=-12 \end{gathered}`
`\begin{gathered} y=x^2+6x+12 \\ y=(-6)^2+6(-6)+12 \\ y=36-36+12 \\ y=12 \end{gathered}`

Only option (1) gives the value of y=0.

Hence option (1) is the correct answer.

Final Answer:

Option first is the correct answer.