Question

The function g(x) is defined as g(x) = 6x2 + 23x – 4. When does g(x) = 0?

a. x = –6 or x =
b. x = –4 or x =
c. x = or x = 6
d. x = or x = 4
ON EDUCATION2020 THE ANSWER IS (D)

Answer 1

6x^2 + 23x - 4 = 0
factorising:-

(6x - 1)(x + 4 ) = 0

x = 1/6 , - 4

Answer 2

x=1/6 and x=-4 are the zeroes of the given equation.

Hence, at these points we will get g(x)=0

Explanation:

We have been given the function:

`g(x)=6x^2+23x-4`

When g(x)=0 we will put g(x)=0 we get:

`6x^2+23x-4=0`

We will factorize the above equation:

`6x^2+24x-x-4=0`

`6x(x+4)-1(x+4)=0`

`(6x-1)(x+4)=0`

Now we will equate both the factors to zero we get:

(6x-1)=0 and (x+4)=0

x=1/6 and x=-4 are the zeroes of the given equation.

Hence, at these points we will get g(x)=0