Question

1. How many milliliters of a 0.184 M NaNO3 solution contain 0.113 moles of NaNO3?ans:614 mL

Answer 1

C=0.184 mol/L
n=0.113 mol

n=CV

V=n/C

V=0.113/0.184=0.614 L = 614 mL

Answer 2

Step-by-step explanation:

The given data is as follows.

Molarity of solution = 0.184 M

Volume of solution = ?

number of moles = 0.113 mol

As molarity is the number of moles present in liter of solvent.

Mathematically, Molarity =
`\frac{\text{No. of moles}}{\text{Volume}}`

Hence, calculate the volume of given solution as follows.

Molarity =
`\frac{\text{No. of moles}}{\text{Volume}}`

0.184 M =
`(0.113 mol)/(volume)`

volume = 0.614 L

As 1 L = 1000 mililiter. Hence convert 0.614 L into ml as follows.

`0.614 L * (1000 ml)/(1 L)`

= 614 ml

Thus, we can conclude that the volume of given solution is 614 ml.