Question

Evaluate the following expression (a + b)^0

Answer 1

1

Explanation:

i just made a B in this class

Answer 2

So,
`(a + b)^0=1`

Explanation:

`(a + b)^0`

To evaluete this expression we apply exponential property

`x^0=1`

IF any expression has exponent 0 then the value is 1 always

for example,
`3^0 =1`

`5^0=1`

`(x+2)^0=1` because exponent is 0

So,
`(a + b)^0=1`