Question

You want to make five-letter codes that use the letters A, F, E, R, and M without repeating any letter. What is the probability that a randomly chosen code starts

with A?

0.10

0.15

0.20

0.25

Answer 1

Any of the given 5 letters can be at the start of the code.
Total choices = 5

We want the code to start with A
Choices in favor = 1

Probability = favorable/total = 1/5 = 0.20

Answer 2

(C)0.20

Explanation:

We are given that we have to make five-letter codes that use the letters A, F, E, R, and M without repeating any letter.

Thus, total number of letters=5

Now, the probability that a randomly chosen code starts with A is given as:

`P=(Favourable outcomes)/(Total number of outcomes)`

`P=(1)/(5)`

`P=0.20`

Therefore, the the probability that a randomly chosen code starts with A is 0.20.

Hence, option C is correct.