If f(x)=the square root of x+12 and g(x)=2 times the square root of x, what is the value of (f-g)(144)?

asked Jul 9, 2018 183k views

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If (f-g)(144) plug 144 for x and g

You get f(x) = f(144) = √144 + 12 = 12 + 12 = 24

g(x) = g(144) = 2√144 = 2*12 = 24

f-g = 24-24 = 0

Jozi answered Jul 12, 2018

by Jozi

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$(f-g)(144) = √(144)+12-2 √(144) \\(f-g)(144) = 12+12-2*12 \\ (f-g)(144) = 24-24 \\ (f-g)(144) = 0$

Megastep answered Jul 14, 2018

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