First find the rate of growth
The formula is
A=p e^rt
A 6500
P 5000
R rate of growth?
E constant
T 2 hours
Solve the formula for r
R=[log (A/p)÷log (e)]÷t
R=(log(6,500÷5,000)÷log(e))÷2
R=0.1312 (rate of growth)
Now predict how many bacteria will be present after 18 hrs
A=p e^rt
A ?
P 5000
R 0.1312
E constant
T 18 hours
A=5,000×e^(0.1312×18)
A=53,039.5 round your answer to get
A=53040....answer