Question

Find the 12th partial sum of the summation of negative 2i minus 10, from i equals 1 to infinity.

25

40

−276

72

Answer 1

The answer to your question is C.−276

Answer 2

The given equation is:

x = - 2i – 10

Calculating for values of i = 1 to 12

x (1) = -2 – 10 = -12

x (2) = -4 – 10 = -14

x (3) = -6 – 10 = -16

x (4) = -8 – 10 = -18

x (5) = -10 – 10 = -20

x (6) = -12 – 10 = -22

x (7) = -14 – 10 = -24

x (8) = -16 – 10 = -26

x (9) = -18 – 10 = -28

x (10) = -20 – 10 = -30

x (11) = -22 – 10 = -32

x (12) = -24 - 10 = -34

Getting the sum of all:

12th partial sum = -276