Question

A player shoots a basketball from a height of 6 feet. The equation, h = -16t 2 + 25t + 6, gives the height, h , of the basketball after t seconds. Describe the height, rounded to the nearest tenth of a foot, of the basketball after 1.5 seconds, assuming no other player touches the ball.

_______ feet above the ground.

Answer 1

h = -16t^2 + 25t + 6.....t = 1.5
h = -16(1.5^2) + 25(1.5) + 6
h = -16(2.25) + 37.5 + 6
h = -36 + 37.5 + 6
h = 7.5 <==

Answer 2

h(1.5)=-16(2.25)+25(1.5)+6

h(1.5)=7.5 ft

So at t=1.5 seconds, the height of the ball is 7.5 ft above the ground.