We are ask to find f ⁻ ' (x)
To find the f ⁻ ' (x), make f(x) =y then solve for x
When you are done, invert the variables.
That is;
f(x) = 3x + 2 / 4+x
y = 3x + 2 / 4 + x
solve for x
3x + 2 = y(4+ x)
3x + 2 = 4y + yx
subtract yx from both-side of the equation
3x - yx + 2 = 4y
subtract 2 from both-side of the equation
3x - yx = 4y -2
x (3 - y ) = 4y - 2
divide both-side by 3-y
x = 4y - 2 / 3-y
f ⁻ ' (x) = 4x - 2 / 3 - x