Question

A substance contains 35.0 g nitrogen, 5.05 g hydrogen, and 60.0 g of oxygen. how many grams of hydrogen are there in a 153-g sample of this substance

Answer 1

m(N)=35.0 g
m(H)=5.05 g
m(O)=60.0 g
m₁=153 g

m₀=m(N)+m(H)+m(O)

w(H)=m(H)/m₀=m(H)/[m(N)+m(H)+m(O)]

m₁(H)=w(H)m₁=m₁m(H)/[m(N)+m(H)+m(O)]

m₁(H)=153×5.05/[35.0+5.05+60.0]=7.72 g

7.72 g

Answer 2

The amount of hydrogen in the substance is 7.72g

Step-by-step explanation:

The mass of the substance is the sum total of masses of the three element. Which implies ;

Total mass of substance = 35g of N +5.05g of H + 60.0g of O =100.05g

Using the percentage composition approach

% of N = 35/100.05 × 100 = 34.98 %

% of H = 5.05/100.05 ×100 =5.047%

% of O = 60.0/100.05 ×100=59.97%

Therefore in a mass of 153g of the substance, there will be 34.98% of N, 5.047% of H and 59.97% of O.

For H: 5.047% of 153g =(5.047/100)×153g

= 7.72g