First, we establish our hypothesis:
Null hypothesis H0: μ = $1.00
Alternative hypothesis Ha: μ ≠ $1.00
Let’s say X = the sample average cost of a daily newspaper = 0.96
u = population mean cost = 1.00
S = sample standard deviation = 0.18
Calculating for z value:
z = (X – u) / S
z = (0.96 – 1) / 0.18
z = – 0.222
From the standard distribution table at this z value, p-value = 0.4129
Since alpha = 0.01, the decision therefore is:
Do not reject the null hypothesis because the p-value is greater than 0.01. There is enough evidence to support the claim that the mean cost of newspapers is $1.