Question

airplane releases a ball as it flies parallel to the ground at a height of 195m, the ball lands on the ground at exactly 195m from the release piont, calculate the speed v of the plane

Answer 1

h=195; x=195
v=x/t. If someting falls down but hast already a certain Speed in a horizontal direction you have to differ between the horizontal and the vertical Speed/ acceleration: x=v×t; y= 1/2×g×t^2. y and h are usually the Same.
h=1/2×g×t^2. t^2=(2×h):g. t=√(2×h):g
v=x/√(2×h):g

Answer 2

Velocity of plane = 30.93 m/s

Step-by-step explanation:

Considering vertical motion of ball

Initial velocity, u = 0 m/s

Acceleration , a = 9.81 m/s²

Displacement, s = 195 m

We have equation of motion s= ut + 0.5 at²

Substituting

s= ut + 0.5 at²

195 = 0 x t + 0.5 x 9.81 x t²

t = 6.31 seconds

Now considering horizontal motion of ball

Acceleration , a = 0 m/s²

Displacement, s = 195 m

Time, t = 6.31 s

We have equation of motion s= ut + 0.5 at²

Substituting

s= ut + 0.5 at²

195 = u x 6.31 + 0.5 x 0 x 6.31²

u = 30.93 m/s

Velocity of plane is horizontal initial speed of ball = 30.93 m/s

Velocity of plane = 30.93 m/s