Question

Two charges separated by a distance of 1 meter exert a 2-n force on each other. if the magnitude of each charge is doubled, the force on each charge is

Answer 1

Force will be 4 times bigger

Answer 2

8N

Step-by-step explanation:

coulomb's law is applied in finding the solution to this problem

the law states that "for two point charges separated by a finite distance, the magnitude of force between them id directly proportional to the product of the charges and inversely proportional to the square of the distance between them".

mathematically, F= kq₁q₂/ r²

inital force exerted, F=2N

distance =1m

2=kq₁q₂/ (1)²

2× 1=k × q₁q₂

k=2/q₁q₂

when magnitude of charge is doubled

F¹=kq₁q₂/ r²

new force F¹ =
`(2)/(q_(1)q_(2) )` ×
`(2q_(1) 2q_(2) )/(1^(2) )`

=2×2×2

=8N