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Given: PQ ||BC (PQ parallel to BC). Find the length of AQ.A. 11B. 12C. 18D. 9

Given: PQ ||BC (PQ parallel to BC). Find the length of AQ.A. 11B. 12C. 18D. 9-example-1
User Carmensita
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1 Answer

21 votes
21 votes

Since PQ and BC are parallel, we have the following:

That is to say, triangles APQ and ABC are similar. Since they are similar, their sides are proportinal. We can then see this relation in the following equation:


(12+6)/(6)=(18+x)/(x)

Where x is the lenght of AQ. We know rearrange the equation


(18)/(6)=(18+x)/(x)
3=(18+x)/(x)
3x=18+x
2x=18
x=9

And so, the lenght of AQ is 9

Given: PQ ||BC (PQ parallel to BC). Find the length of AQ.A. 11B. 12C. 18D. 9-example-1
User Tom Johnson
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