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Paul and Scott were solving the same problem. Who is wrong? Explain their error. Paul Scott __________________ log 3x=9 log 3x=9 3^x=9 x=3^9 3^x=3^2 x=19,683 x=2
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Paul and Scott were solving the same problem. Who is wrong? Explain their error.

Paul Scott
__________________

log 3x=9 log 3x=9
3^x=9 x=3^9
3^x=3^2 x=19,683
x=2

User JKLM
by
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1 Answer

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The answer is: log3(x)=9
x=3⁹
x=19 683


3 ^x = 9. 3^x = 3^2, x = 2 . If we have log˙(x) a = b then: a = x^b, Paul wrote it in a form: b = x^a. Scott was right. He wrote: 3^9 = x and as a result he had: x = 19,683.


So Paul is Wrong
User Yang Peiyong
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