Question

Oh Plz help - I can't handle this one :)

Answer 1

a. cynlinder
A = 2 *pi * r^2 + 2 * pi * r * h
A = 2 * pi * 5^2 + 2 * pi * 5 * 10
A = 50 pi + 100 pi
A = 150 * pi cm^2 (Exact Answer)
A = 471 cm^2 (Decimal Approximation)

b. A(triangles)
A = (1/2) * b * h * 2
A = (1/2) * 4 * 1.5 * 2
A = 6 m^2
A(rectangles)
A = L * W
A = 4 * 6 + 2.5 * 6 * 2
A = 24 + 30
A = 54 m^2
Total area = 6 + 54 = 60 m^2

c. A(rectangular prism)
A = 2LW + 2LH + 2WH
A = 2 * 5.2*2.4 + 2 * 5.2 * 3.5 + 2 * 2.4 * 3.5
A = 78.16 ft^2

d. A(rectangular prism)
A = 2LW + 2LH + 2WH
A = 2 *12 * 6 + 2 * 12 * 4.5 + 2 * 6 * 4.5
A = 306 ft^2

e. You have a large box to wrap and need to know how much wrapping paper will be needed to wrap the box.
The dimensions of the box are L = 10 in., W = 4 in., H = 6 in.

Answer 2

a: 5^2*pi = 25pi =~ 78.5375, 10*5*2*pi = 100pi =~ 314.15, 314.15+2(78.5375) = 471.23 cm^2

b: 4*0.5*1.5 = 3, 6*4 = 24, 6*2.5 = 15.5, 15.5*2 + 3*2 + 24 = 61m^2

c: 5.2*3.5 = 18.2, 2.4*3.5 = 8.4, 2.4*5.2 = 12.48, 12.48*2 + 8.4*2 + 18.2*2 = 78.16ft^2

A bit late but hope it helps