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A complex number, (a + bi), multiplied by (2 + 3i) and added to -i gives the product of (-11 +5i) and (1-i) a= ? b=?
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A complex number, (a + bi), multiplied by (2 + 3i) and added to -i gives the product of (-11 +5i) and (1-i) a= ? b=?
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Nov 10, 2018
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A complex number, (a + bi), multiplied by (2 + 3i) and added to -i gives the product of (-11 +5i) and (1-i)
a= ? b=?
Mathematics
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Chari
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working backwards (-11 + 5i)(1 - i) = -11 + 11i + 5i +5 = -6 + 16i
subtracting -i we have -6 +16i - (-i) = -6 + 17i
(a + bi)(2 + 3i) = 2a + 3ai + 2bi + 3bi^2 = 2a - 3b + (3a + 2b)i
2a - 3b + (3a + 2b)i = -6 + 17i
EQuating real and imaginary parts:-
2a - 3b = - 6
3a + 2b = 17
solving this for a and b gives a = 3 and b = 4
Siri
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Nov 17, 2018
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