210k views
1 vote
a body of mass 1 kg is placed at a distance of 2 m from another body of mass 10 kg. At what distance from the body of mass 1 kg, another body must be placed so that the net gravitational force acting on the body of mass 1 kg is zero

1 Answer

3 votes

To answer this problem, we will use the formula for gravitational force:

F = G m1 m2 / r^2

Where,

G = gravitational constant (6.67 * 10^-11)

m = mass of a body

r = distance between two bodies

To have a net gravitational force equal to zero acting on body of mass 1 kg, then the forces of 1 kg and 10 kg bodies and 1 kg and 5 kg bodies should be equal.

F1 (1 kg and 10 kg) = F2 (1 kg and 5 kg)

Therefore,

(1 kg) (10 kg) / (2 m)^2 = (1 kg) (5 kg) / r2^2

Calculating for r2 (distance of another body 5 kg from body of mass 1 kg):

r2^2 = 2

r2 = 1.41 m (ANSWER)

Therefore another body of mass 5 kg should be placed 1.41 m from body of mass 1 kg to have a net gravitational force equal to zero.

User Sagar Kharche
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.