Question

Mike and adam left a bus terminal at the same time and traveled in opposite directions. mike’s bus was in heavy traffic and had to travel 20 mi/h slower than adam’s bus. after 3 hours, their buses were 270 miles apart. how fast was each bus going?

Answer 1

adam's bus speed = a
mike's bus speed = m
total distace = t

m = a - 20

after 3 hour:

3 * (m + a) = t
3 * (m + a) = 270
3m + 3a = 270
[ 3 * (a - 20) ] + [ 3 * a ] = 270
[ 3a - 60 ] + 3a = 270
3a - 60 + 3a = 270
3a + 3a = 270 + 60
6a = 330

their speed:
a = 55
m = 55 - 20 = 35