Question

Use the specific heat of water to determine how much heat is required to raise the temperature of 50.0g of water from 35oc to 55oc.

Answer 1

the specific capacity of water is 4186
so use this formula that is Q=mcΔt
= (0.05)(4186)(55-35)
=4186J

Answer 2

There is 4184 Joule of energy required

Step-by-step explanation:

Step 1: Data given

Mass of water = 50.0 grams

Initial temperature of water = 35.0 °C

Final temperature = 55.0 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the heat

Q = m*c*ΔT

⇒ Q = the heat transfer (in Joules)

⇒ m = the mass of water = 50.0 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change of temperature of the water = T2 - T1 = 55.0°C - 35.0 °C = 20.0 °C

Q = 50.0g * 4.184 J/g°C * 20.0 °C

Q = 4184 J

There is 4184 Joule of energy required