Question

Linear function A and linear function B both have the same input values as shown below. Why will the output values for linear function A always be different than the corresponding output values for linear function B?

Answer 1

I would say:
The initial values of the two functions are different, and the rates of change of the two functions are the same.

(AKA B)

Answer 2

Answer: The initial values of the two functions are different but the rate of change is same.

Explanation:

For function A ,

When x=1, the initial value of function A=3

The rate of change of function A =
`(y_2-y_1)/(x_2-x_1)=(7-3)/(3-1)=(4)/(2)=2`

For function B,

When x=1, the initial value of function B= 4

The rate of change of function A =
`(y_2-y_1)/(x_2-x_1)=(8-4)/(3-1)=(4)/(2)=2`

Since, 3≠4, thus, the initial values of two function is different.

But the rate of change is same.

Thus, Function A has odd output values, because it has an odd number as initial value and 2 as constant rate of change.

Function B has even output values, because it has an even number as initial value and 2 as constant rate of change.