Question

May you help me please ? Thanks!

Answer 1

a

`sin(51^o) = (y)/(hypotenuse) \to \ y=sin(51^o)*12 \approx 9.33 \ units`

b

`sin \theta= (opposite)/(hypotenuse)= (12)/(13) \approx 0.9231 \ \to \ m \angle \theta \approx67.38^o`

с

`tan(13^o)=(opposite)/(adjacent)= (x)/(24) \ \to \ x= tan(13^o)*24\approx5.54 \ units`

d

`sin(20^o) = (opposite)/(x) = (10)/(x) \to \ x= (10)/(sin(20^o)) \approx29.24 \ units`