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How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 34.5 grams of sodium hydroxide in the single replacement reaction below? Unbalanced equation: Na + H2O --->
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How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 34.5 grams of sodium hydroxide in the single replacement reaction below?

Unbalanced equation: Na + H2O ---> NaOH + H2

User Chrismead
by
6.9k points

1 Answer

5 votes

Answer:

35.567mL

Step-by-step explanation:

Simple, density = mass/volume

Volume = mass/density

Which yields

34.5/0.97 = 35.567milliliters

User Pfunk
by
6.4k points
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