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4 votes
The x-intercept of the graph of f(x)= 3log(x-5)+2 is:

2 Answers

5 votes

Answer:

10^-2/3 +5

Explanation:

User Nielsen
by
8.4k points
2 votes

Answer:
\frac{1}{e^{(2)/(3)}}+5 or 5.51

Explanation:

The given function :
f(x)= 3\log(x-5)+2

We know that , the x-intercept is the point on graph( basically intersection of graph and x-axis) where y coordinate is zero.

I.e. for x-intercept of function , f(x) =0

i.e.
0= 3\log(x-5)+2


\Rightarrow\ \log(x-5)=(-2)/(3)

Taking exponent on both sides , we get


x-5=e^{(-2)/(3)}\\\\\Rightarrow\ x=e^{(-2)/(3)}+5\ \ or\ \ x=\frac{1}{e^{(2)/(3)}}+5

On simplification ,
\frac{1}{e^{(2)/(3)}}+5\approx5.51.

Hence , the x-intercept of the graph f(x)=
\frac{1}{e^{(2)/(3)}}+5 or 5.51.

User Saliou
by
8.9k points