28.9k views
1 vote
Solve the system of equations below. 4x+y=16 2x+3y=-2 A. (4,-5) B. (5,-4) C. (5,4) D. (-5,4)

2 Answers

7 votes
your answer is (5,-4)
User Aquinas
by
5.6k points
2 votes

Answer:

Option B is correct.

(5, -4)

Explanation:

Given the system of equations:


4x+y = 16 ......[1]


2x+3y = -2 .....[2]

Multiply equation [2] by 2 both sides we have;


4x+6y = -4 .....[3]

Subtract equation [3] from [1] we have;


4x+y-4x-6y= 16+4

Combine like terms;


-5y = 20

Divide both sides by -5 we have;

y = -4

Substitute this value y in [1] we have;

4x+(-4) = 16

⇒4x - 4 = 16

Add 4 to both sides we have;

4x = 20

Divide both sides by 4 we have;

x = 5

therefore, the solutions of the given systems is, (5, -4).

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.