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Determine the empirical formula for a compound that is 70.79% carbon, 8.91% hydrogen, 4.59% nitrogen, and 15.72% oxygen.

1 Answer

4 votes
Assume 100g of substance

C = 70.79/12 = 5.899
H = 8.91/1 = 8.91
O = 4.59/16 = 0.287

Divide by the smallest

21 : 31 : 1

c21h31o
User BraedenP
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