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Prove that for all natural numbers n 8n-3n is divisible by 5
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Prove that for all natural numbers n 8n-3n is divisible by 5

User Jay Regal
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8n-3n=5n

One of the factors is 5, so the number is divisible by 5.

User Nimesh Nikum
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8n-3n=n(8-3)=n(5)=5n=5 times n
5 is a factor of 5n so it is evenly divisible by 5
and since n is a natural number, it is the multiplier to make multipules of 5

User Havald
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