Prove that for all natural numbers n 8n-3n is divisible by 5

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asked May 6, 2018 47.6k views

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Havald · Answer 1 · 2018-05-10T22:31:34+0000

8n-3n=n(8-3)=n(5)=5n=5 times n
5 is a factor of 5n so it is evenly divisible by 5
and since n is a natural number, it is the multiplier to make multipules of 5

Prove that for all natural numbers n 8n-3n is divisible by 5

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