Question

A 0.023 kg beetle is sitting on a record player 0.15 m from the center of the record. if it takes 0.070 n of force to keep the beetle moving in a circle on the record, what is the tangential speed of the beetle? 0.68 m/s 0.46 m/s 0.33 m/s 0.11 m/s

Answer 1

the answer is 0.68 meters per second, swagteam

Answer 2

Tangential speed is 0.68 m/s

Step-by-step explanation:

It is given that,

Mass of the beetle, m = 0.023 kg

It is placed at a distance of 0.15 m from the center of record i.e. r = 0.15 m.

If it takes 0.070 n of force to keep the beetle moving in a circle on the record i.e. centripetal force acting on it is, F = 0.070 N

We have to find the tangential speed of the beetle. The formula for centripetal force is given by :

`F=(mv^2)/(r)`

v is tangential speed

`v=\sqrt{(Fr)/(m)}`

`v=\sqrt{(0.070* 0.15)/(0.023)}`

v = 0.675 m/s

or

v = 0.68 m/s

Hence, the correct option for tangential speed is (A).