Question

Solve the quadratic equation 5x2 - 125 = 0.

x = -5

x = 5

x = ±5

x = ±25

Answer 1

Let's solve this with the quadratic formula, which is:
`x_(1,\:2)=(-b\pm √(b^2-4ac))/(2a)`
Let's plug in the values:

`(-0+√(0^2-4\cdot \:5\left(-125\right)))/(2\cdot \:5)`
Remove exponents:

`=(-0+√(0-\left(-125\right)\cdot \:4\cdot \:5))/(2\cdot \:5)`
Simplify.

`=(-0+√(0-\left(-125\right)\cdot \:4\cdot \:5))/(10)`

`=(√(-\left(-125\right)\cdot \:20))/(10)`

`=(50)/(10)`

`=\pm 5`

This leaves us with the final solutions being:

`x=5,\:x=-5`

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish