Answer: d. rotation, then translation
Explanation:
In the given figure, there is a pair of triangles ΔMNQ and ΔPQN.
When we rotate ΔMNQ about point Q 180° counter clockwise to form ΔM'N'Q',[such that the sides of ΔM'N'Q will be parallel to corresponding sides of ΔPQN].
Then we apply translation towards right so that it will became ΔPQN.
Hence, the right transformation(s) can map MNQ onto PQN are rotation, then translation
.