Question

If a baker doubles a recipe that calls for 6-2/3 cups of flour. How many cups will be needed in all?

Answer 1

To double the recipe calling for 6-2/3 cups of flour, convert 6-2/3 to an improper fraction (20/3), multiply by 2 to get 40/3, and then convert back to a mixed number, resulting in 13 1/3 cups needed.

Step-by-step explanation:

To calculate the total amount of flour needed when the recipe is doubled, we need to multiply the original amount by two. The original recipe calls for 6-2/3 cups of flour. Doubling this amount means we need two times 6-2/3 cups, which is 6-2/3 cups + 6-2/3 cups.

To add these fractions, first convert 6-2/3 to an improper fraction, which is 20/3 (since 6 × 3 + 2 = 20, and the denominator remains as 3).

Next, we multiply 20/3 by 2 to find the doubled amount:

20/3 × 2 = 40/3

Finally, convert 40/3 back to a mixed number for our final answer:

40/3 = 13 1/3 cups. So, the baker will need 13 1/3 cups of flour in total.

Answer 2

Hey there!

The easiest way I could think to do this is by converting your mixed number to an improper fraction and multiplying the fraction by 2, or 2 over 1.


`6 (2)/(3) = 6*3+2 = (20)/(3)`


`(20)/(3) * (2)/(1)`

To multiply fractions, you can just multiply the numerators and denominators and simplify, if applicable.


`(20)/(3) * (2)/(1) = (40)/(3)`

Since you can't simplify this fraction in its improper form, just convert it back into a mixed number.


`(40)/(3) = 13 (1)/(3)`

So, your answer will be
`13 (1)/(3)`.

Hope this helped you out! :-)